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X^2-4.8X+2.4=0
a = 1; b = -4.8; c = +2.4;
Δ = b2-4ac
Δ = -4.82-4·1·2.4
Δ = 13.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{13.44}}{2*1}=\frac{4.8-\sqrt{13.44}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{13.44}}{2*1}=\frac{4.8+\sqrt{13.44}}{2} $
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